Math, asked by Mittalsanchit64, 1 year ago

logx/log5=log9/log1/3

Answers

Answered by ROYALJATT
6
HELLO FRIENDS,
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Logx/log5=log9/log1/3
(by log property Logx/logy=logx-logy)
Logx-log5=log9-log1/3
Logx-log5=log9-log1-log3
Logx-Log5 = Log9-Log4
⇒Logx-Log5 = Log5
⇒Logx = Log5+Log5
⇒Logx = Log10

⇒ x=10
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Best of luck ;)
ROYALJATT

ROYALJATT: click on thanks
Mittalsanchit64: ty bro
ROYALJATT: pleasure
ROYALJATT: click on thanks
Answered by pablo
2
Logx/log5=log9/log1/3
(by log property Logx/logy=logx-logy)
Logx-log5=log9-log1/3
Logx-log5=log9-log1-log3
Logx-Log5 = Log9-Log4
⇒Logx-Log5 = Log5
⇒Logx = Log5+Log5
⇒Logx = Log10
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