√Logx/logy|klogz= answer this for 100 points
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5
Answer:
Answer:x^(logy-logz) .y^(logz-logx) .z^(logx-logy)=1
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1
Answer:
x√Logx/logy|klogz=√Logx/logy|klogz=z√Logx/logy|klogz=
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