Question

logxbase2+log(x+2)base 2=3 find x​

Answer 1

Answer:

X = 1

Step-by-step explanation:

$log_{2}(x) + log_{2}(x + 2) = 3 \\ \\ \\ log_{2}(x(x + 2)) = 3 \\ \\ \\ {x}^{2} + 2x = 3 \\ \\ \\ {x}^{2} + 2x - 3 = 0 \\ \\ \\ (x - 1)(x + 3) = 0 \\ \\ \\ x = 1$

Answer 2

Answer:

$log_{2}(\pi + 2 ) - log_{2}\pi = 3$