Long distance train schedule to reach destination 19 hours after 10 hours of journey due to the distribution of rail traffic the train has been station for 1 hour if the average speed of a train is 100 km per hour at what speed should i travel to cover the same amount of time
Answers
According to the given information
Total journey time = 19 hours
The train has completed a 10 hour journey.
The average speed of train is 100km/hr.
So the total distance in 19 hours at a speed of 100km/h is = 19 (100) = 1900km
The train has moved for 10 hours.
So it has completed a disatnce in 10 hours = 10(100) = 1,000 km
It had to wait due to the distribution of rail traffic.
So the train completed the distance of 1,000km in 11 hours.
NOW
remaining distance = 1900 - 1000 = 900 km
remaining times = 19 hours - 11 hours = 8 hours
New Average Speed = Distance / Time
= 900 / 8 = 112.5 km/h
So the train had to move with a speed of 112.5 km/h to complete the journey in the same time (to cover the delay).
Given,
Total time = 19 hrs
Journey completed = 10 hrs
The average speed of train is 100km per hour.
Total distance = Speedx time = 19 hrsx 100 km/hrs= 1900 km
Completed distance in 10 hours.
= 10hrs x 100 km/hrs = 1,000 km
Due to the distribution of rail traffic waiting time 1 hour
total journey time = 10 hrs journey + 1 hour waiting time = 11 hrs and distance covered is same i.e. 1,000 km in 11 hrs.
NOW
Time left to reach at destination = 19-11= 8 hrs
distance to be covered in 8 hrs = 1900-1000= 900 km
Speed required to reach on same time = Balance Distance / balance Time
= 900 / 8 = 112.5 km/h
So the train should maintain a speed of 112.5 km/h to complete the journey in the same time (to cover the delay of 1 hrs).