Question

long division method 184 , 230 and 276
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Answer 1

Answer:

46

Step-by-step explanation:

Given numbers are 184, 230, and 276.

Applying Euclid's division lemma to 184 and 230, we get

230 = 184 × 1 + 46

184 = 46 × 4 + 0

The remainder at this stage is zero.

So, the divisor at this or the remainder at the previous stage i.e., 46 is the HCF of 184 and 230.

Also,

276 = 46 × 6 + 0

∴  HCF of 276 and 46 is 46

HCF (184, 230,  276) = 46

Hence, the required HCF of 184, 230 and 276 is 46.