Look at the alongside figure and from the measures given
find the area of total figure.
AD=20m., CD=34 m.,
BC= 50 m., BD=52 m.
mZ DAB=90°
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Step-by-step explanation:
ar. of DAB= 1/2×b×h
=1/2×20×52
=1/2×10×52
=520m^2
ar. of BCD =1/2× b ×h
=1/2×34×50
=1/2×34×25
=850m^2
area of figure= ar. of DAB+ ar. of BCD
= 520+850
=1370m^2
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