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Find x, y and Z in the given figure.
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Answered by
3
Hi ,
1 ) 2y + 8 + 142 = 180° [ linear pair ]
2y + 150 = 180
2y = 180 - 150
2y = 30
y = 30/2
y = 15 ---- ( 1 )
2 )( 4x + 6 ) + ( 2y + 8 ) = 180
[ since sum of interior angles lie same
side of the transversal ]
4x + 6 + 2 × 15 + 8 = 180
[ from ( 1 ) , y = 15 ]
4x + 6 + 30 + 8 = 180
4x + 44 = 180
divide each term with 4 , we get
x + 11 = 45
x = 45 - 11
x = 34 ----( 2 )
3 ) z = 142°
[ since exterior alternate angles are equal ]
I hope this helps you.
:)
1 ) 2y + 8 + 142 = 180° [ linear pair ]
2y + 150 = 180
2y = 180 - 150
2y = 30
y = 30/2
y = 15 ---- ( 1 )
2 )( 4x + 6 ) + ( 2y + 8 ) = 180
[ since sum of interior angles lie same
side of the transversal ]
4x + 6 + 2 × 15 + 8 = 180
[ from ( 1 ) , y = 15 ]
4x + 6 + 30 + 8 = 180
4x + 44 = 180
divide each term with 4 , we get
x + 11 = 45
x = 45 - 11
x = 34 ----( 2 )
3 ) z = 142°
[ since exterior alternate angles are equal ]
I hope this helps you.
:)
royboy:
i was giving this answer
Answered by
0
HI!!
HERE IZ UR ANSWER.
2y + 8 + 142 = 180 (sum of linear pair is 180)
So, 2y = 180-150 = 30
y = 30/2 = 15 --------- (1)
Also,
4x + 6 + 2y + 8 = 180 (sum interior angles on same side of transversal)
from eqn 1,
y = 15
So,
4x + 6 + 2 * 15 + 8 = 180
4x + 44 = 180
x = 34
And,
z = 142, because of alternate exterior angles.
HOPE IT HELPS!!
HERE IZ UR ANSWER.
2y + 8 + 142 = 180 (sum of linear pair is 180)
So, 2y = 180-150 = 30
y = 30/2 = 15 --------- (1)
Also,
4x + 6 + 2y + 8 = 180 (sum interior angles on same side of transversal)
from eqn 1,
y = 15
So,
4x + 6 + 2 * 15 + 8 = 180
4x + 44 = 180
x = 34
And,
z = 142, because of alternate exterior angles.
HOPE IT HELPS!!
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