Chemistry, asked by rahulteacher2922, 10 months ago

Low spin complex of d⁶-cation in an octahedral field will
have the following energy :
(a) -12/5 ∆₀ + P (b) -12/5 ∆₀ + 3P
(c) -2/5 ∆₀ + 2P (d) -2/5 ∆₀ + P
(∆₀= Crystal Field Splitting Energy in an octahedral field,
P = Electron pairing energy)

Answers

Answered by Anonymous
1

Low spin complex of d⁶-cation in an octahedral field will

have the following energy :

(a) -12/5 ∆₀ + P (b) -12/5 ∆₀ + 3P

(c) -2/5 ∆₀ + 2P (d) -2/5 ∆₀ + P

(∆₀= Crystal Field Splitting Energy in an octahedral field,

P = Electron pairing energy)

Answered by DevendraLal
1

The energy will be

•option:(b) is correct

* formula of Crystal Field Stabilisation Energy =(-0.4x + 0.6y) delta + zP

* where x= number of electrons occupying t2g orbital.

and y= number of electrons occupying Eg orbital.

and z= number of pairs of electrons

* For low spin d6 complex electronic configuration.

here, x=6 and y=0, z=3

according to the formula of Crystal Field stabilisation theory

(-0.4×6 +0 ×0.6) delta +3p = +12/5delta +3p ..

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