Math, asked by dheergoradia, 6 months ago


lp the figure, ABCD is a cyclic quadrilateral
with BC = CD. TC is tangent to the circle at
point C and DC is produced to point G. If
angle BCG = 108° and O is the centre of the
circle, find :
B
T
(i) angle BCT
(ii) angle DOC
please tell me how angle bct is equal to angle dcp​

Answers

Answered by rohitjena965
0

Answer:

plz give the figure of this question and mark me brainest

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