Question

<ABC is bisected by BX. O is any point on BX & POQ is perpendicular to BX. prove that PO = OQ.
.....plzz tell clearly on paper

Answer 1

In ∆POB & ∆QOB,
Angle OBQ=Angle OBP--------(given)
angle POB=Angle QOB=90° -----------(given)
and
OB=OB --------(common)
so, by ASA congruence criterion,
∆POB=~ ∆QOB
so, by CPCT,
OP=OQ
H.P.

Answer 2

please mark my answer as a brain list