Question

(lx-my)2-(mx+ly)2 factorize
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Answer 1

Here we go bud,

${(lx - my) }^{2} - {(mx + ly)}^{2} \\ = (lx - my - mx - ly)(lx - my + mx + ly) \\ (l(x - y) - m(x + y))(l(x + y) + m(x - y))$

Answer 2

Answer:

This is your answer

Step-by-step explanation:

lx−my)

2

−(mx+ly)

2

=(lx−my−mx−ly)(lx−my+mx+ly)

(l(x−y)−m(x+y))(l(x+y)+m(x−y))

HOPE THIS HELP YOU

THANKS ☺️