Question

m=10, n=6;
m - = 9% + n + (++n/2 - --n);​

Answer 1

Answer:

We have,

int m = 10, n = 6.

Program:

m-= 9%++n + ++n/2;

Output:

4

Explanation:

m = 10 - [9%++n + ++n/2]

  = 10 - [9%7  +  8/2]

  = 10 - [2 + 4]

  = 10 - 6

  = 4.

Modulo operator(%) computes remainder.