Question

M
14. In the adjoining figure, ABCD is a trapezium in which AB || DC.
If M and N are the mid-points of AC and BD respectively, prove
1
that MN = (AB-CD).
2
[Hint. Join CN and produce it to meet AB at E.
Then, ACDN = AEBN. So, CD = EB and CN = NE.
1
1
MN AE (why ?) (AB - EB) (AB - CD).
2
2
=
D​

Answer 1

Where's the figure mate..........

Answer 2

Step-by-step explanation:

M

14. In the adjoining figure, ABCD is a trapezium in which AB || DC.

If M and N are the mid-points of AC and BD respectively, prove

1

that MN = (AB-CD).

2

[Hint. Join CN and produce it to meet AB at E.

Then, ACDN = AEBN. So, CD = EB and CN = NE.

1

1

MN AE (why ?) (AB - EB) (AB - CD).

2

2

=

D