Question

m^2-2(m+1)x+m^2=0
The root of each of the following quadratic equation are real and equal

Answer 1

Step-by-step explanation:

The given equation is x

2

+2(m−1)x+(m+5)=0

For the equation to have real and equal roots, the discriminant should be 0.

∴[2(m−1)]

2

−4(m+5)=0

⇒4(m

2

−2m+1)=4(m+5)

⇒m

2

−3m−4=0

⇒(m−4)(m+1)=0

∴m=4 or m=−1