Question

(m) 211
The approximate value of x where x = sin 2° cos 2º, is :

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Answer 1

Given : x  = sin2°Cos2°

To find : The approximate value of x

Solution:

x  = sin2°Cos2°

=> x  = 2sin2°Cos2°/2

=> x = Sin4°/2

180° = π

=> 1° = π/180

=> 4° = 4π/180

=> 4° = 2π/90

=> x = Sin( 2π/90) / 2

Multiplying & dividing by π/90

=> x = ( π/90) Sin( 2π/90) / (2(π/90) )

=> x = ( π/90)   Sin( 2π/90) / (2π/90 )

2π/90 tends to 0

=> Sin Sin( 2π/90) / (2π/90 ) = 1

=> x =  π/90

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