m√5 = m√2 + 1
Find m
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Here is your answer hope it helps you
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Hey Mate !
Here is your solution :
Given,
=> m√5 = m√2 + 1
=> m√5 - m√2 = 1
By taking m as common in L.H.S,
=> m ( √5 - √2 ) = 1
=> m = 1 ÷ ( √5 - √2 )
By multiplying in numerator and denominator of R.H.S by ( √5 + √2 ).
=> m = 1 ( √5 + √2 ) ÷ ( √5 - √2 ) ( √5 + √2 )
Using identity :
[ ( a + b ) ( a - b ) = a² - b² ]
=> m = ( √5 + √2 ) ÷ { ( √5 )² - ( √2 )² }
=> m = ( √5 + √2 ) ÷ ( 5 - 2 )
=> m = ( √5 + √2 ) / 3
==============================
Hope it helps !! ^_^
Here is your solution :
Given,
=> m√5 = m√2 + 1
=> m√5 - m√2 = 1
By taking m as common in L.H.S,
=> m ( √5 - √2 ) = 1
=> m = 1 ÷ ( √5 - √2 )
By multiplying in numerator and denominator of R.H.S by ( √5 + √2 ).
=> m = 1 ( √5 + √2 ) ÷ ( √5 - √2 ) ( √5 + √2 )
Using identity :
[ ( a + b ) ( a - b ) = a² - b² ]
=> m = ( √5 + √2 ) ÷ { ( √5 )² - ( √2 )² }
=> m = ( √5 + √2 ) ÷ ( 5 - 2 )
=> m = ( √5 + √2 ) / 3
==============================
Hope it helps !! ^_^
Anonymous:
Thanks for Brainliest!!
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