Question

M+D+I=74.D+I is 46 greater than M.I is 60% less than D.what is the weight of D?; M+D+I=74.D+I is 46 greater than M.I is 60% less than D.what is the weight of D?

Answer 1

M+D+I=74 -----(1)

D+I= M+46 -----(2)

put (2) in (1)

M+(M+46) = 74

2M = 74-46

2M = 28

M = 14. ----(3)

now,

I = D-(60/100)D

I = (40/100)D

I = (2/5)D. ----(4)

now,

M+D+I=74

now from (3) & (4)

14+D+(2/5)D=74

(7/5)D=60

D=300/7

D=42.85

therefore, required weight of D is 42.85.

hope this will help u!