Question

M is the mid point of AB. AC and BD are perpendicular to CD. Prove that triangle ACM is congruent to triangle BDM.​

Answer 1

Step-by-step explanation:

triange MAC and triangle MBD

angle MAC=90, Angle MBD=90

both triangle are right angle triangle

seg.AM =seg MB

Hyp cm= Hyp mB

by test Hyp-side

triangle MAC= triangle mBD