M is the midpoint of AB and C is the midpoint of AM. Let the coordinate of A=7y and the coordinate of B=3x. Find the coordinate of C in terms of x and y.
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Given :-
- M is the midpoint of AB .
- C is the midpoint of AM.
- The coordinate of A = 7y.
- The coordinate of B = 3x.
To Find :-
- The coordinate of C in terms of x and y. ?
Formula used :-
- The coordinate of the mid - point of a line is given by adding the values of the two end points and then dividing the result by 2. { or Average of Both end Points.}
Solution :-
→ coordinate of A = 7y .
→ coordinate of B = 3x .
→ M is the Mid Point of AB.
So,
→ coordinate of M = Average of A and B
→ coordinate of M = (A + B)/2
→ coordinate of M = (7y + 3x)/2 .
Now, we have given that, C is the midpoint of AM.
Therefore,
→ The coordinate of point C = Average of A and M .
→ C coordinate = (A + M) / 2
→ C coordinate = [ 7y + {(7y + 3x)/2} ] / 2
→ C coordinate = (14y + 7y + 3x) / (2 * 2)
→ C coordinate = (21y + 3x) / 4
→ C coordinate = (3/4)(7y + x) (Ans.)
Hence, The coordinate of C is (3/4)(7y + x) .
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