m∠LONm, angle, L, O, N is a straight angle. \qquad m \angle LOM = 7x - 92^\circm∠LOM=7x−92 ∘ m, angle, L, O, M, equals, 7, x, minus, 92, degrees \qquad m \angle MON = 6x + 12^\circm∠MON=6x+12 ∘ m, angle, M, O, N, equals, 6, x, plus, 12, degrees Find m\angle LOMm∠LOMm, angle, L, O, M:
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Can't understand.
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is this from khan academy if yes then post a screenshot
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