Question

(m+n)^-1 (m^-1+n^-2)=m^x n^y show that: x+y+z=0

Answer 1

Answer:

m+n)^-1 (m^-1+n^-2)=m^x n^y

Step-by-step explanation:

x+y+z=0

x=64

y=87

z=83