Question

(m-n)^2= [(m+n)^2-4mn . how?​

Answer 1

Answer:

LHS (m-n)²

=m²-2mn+n²

=m²+2mn+n²-4mn

=(m+n)²-4mn=RHS.

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Answer 2

Answer:

(m-n)²

Here is your solution:

= (m-n)² +4mn

= m² + 2 × m × n² - 4mn

= m² + 2mn + n² - 4mn

= m² + n² + (2mn - 4mn)

= m² + n² - 2mn

= (m - n)²

= (m - n) (m - n)

Hope it's helpful.