Chemistry, asked by shubhansanap381, 1 month ago

m- nitroaniline + napthalene ​

Answers

Answered by gyaneshwarsingh882
0

Answer:

Explanation:

This experiments allows you to separate a solid-phase mixture consisting of (i) 2-methoxynaphthalene, (ii) m-nitroaniline, and (iii) benzoic acid using Separatory Funnel extractions.  Since each of these chemicals have similar solubilities in water and ether, you can effect a separation their chemical properties.  For example, benzoic acid is insoluble in water but the benzoate ion is soluble in water.  Therefore, under neutral conditions, the benzoic will partition into the ether layer.  Adding NaOH will neutralize the benzoic acid producing the benzoate ion, which now goes into the aqueous layer, leaving other other two organic compounds in the ether.  Likewise, nitroaniline is not soluble in neutral or basic conditions, but is soluble in acidic solutions. Making the liquid in the Separatory Funnel acidic will allow the nitroaniline to be positively charged, and it will now partition into the aqueous layer.  Isolating the aqueous layers allow you to crystallize the benzoic acid and nitroaniline as describe in this protocol. Final analysis of the isolated chemicals will be done using melt point analysis. You will also need to determine a percent yield for each.

Answered by mohitkkr02
0

Answer:

m- nitroaniline + napthalene

Similar questions