Chemistry, asked by Arifan9879, 7 months ago

ꓥm of 0.05 M weak electrolyte is 50 Sm2mol-1, ꓥm0of it is 440 Sm2mol-1. Calculate α (degree of dissociation) of the electrolyte.​

Answers

Answered by AnupamChaurasiya01
2

Answer:

0.114

Explanation:

 \alpha  =  \frac{ \lambda {}^{0}m }{ \lambda {}^{c} m}

 \alpha  =  \frac{50}{440}  \\  \alpha  =  \frac{5}{44}  \\  \alpha  = 0.114(approx)

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