M tan theta minus 30 is equal to n tan theta + 120
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Tan ( x - 120°) = tan [ 90° + ( 30° + x ) ] = - cot ( 30° + x ).
And tan ( x - 30°) = - tan ( 30° - x ) …………………. (1)
Now the given relation can be rearranged as ---
=> m/n = tan ( x + 120°) / tan ( x - 30°),
=> m/n = - cot ( 30°+ x ) / - tan ( 30° - x )
=> m/n = [ cos (30° + x ) . cos (30° - x ) ] / [sin (30° + x ) . sin (30° - x )]
=> (m/n) = ( cos² 30° - sin² x ) / (sin² 30° - sin²x )
=> (m/n) = ( ¾ - sin² x ) / ( ¼ - sin²x )
Now apply componendo and dividendo.
( m + n )/ ( m – n ) = (1 – 2 sin²x) / ( ½ )
=> ( m + n )/ ( m – n ) = 2 cos 2x ……………………… Proved Proved
Shaun Abraham
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