Question

. m uC TUTDCi ur vucu Tu yrvorrlyure.
4. The perimeter of a square is 12 cm less than the perimeter of a rectangle. Each IT
side of the square is of length 16 cm. While the length of the rectangle is 20 cm, find its
breadth?​

Answer 1

Answer:

given

side of square = 16 cm

length of rectangle(L) = 20 cm

perimeter of square = 4×side

= 4×16

= 64 cm

according to the question

perimeter of square = perimeter of rectangle— 12 cm

64cm=2(L+B)—12cm

64+12=2(20+B)

72÷2=20+B

36—20=B

B=16cm

Answer 2

Answer:

Answer is 18

Step-by-step explanation:

Let the perimeter of square be X and perimeter of rectangle be y

Given :

X = y - 12

Side of a square = 16

Length of rectangle = 20

Solution :

X = 4a = 4*16

X = 64

64 = y - 12

y = 2(20 + b )

64 = 2(20 + b ) - 12

64 + 12 = 2(20 + b )

76 = 2(20 + b )

76/2 = 20 + b

38 = 20 + b

38 - 20 = b

18 = b

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