m(x+y)+n(x-y)-(m^2+mn+n^2)=0
n(x+y)+m(x-y)-(m^2-mn+n^2)=0
Answers
Answered by
10
Step-by-step explanation:
x=m×m+n×n÷m+n
y=m×n÷m-n
Answered by
34
x = (m² + n²)/(m + n) , y = mn/(m - n)
Step-by-step explanation:
m(x+y)+n(x-y)-(m²+mn+n²)=0
n(x+y)+m(x-y)-(m²-mn+n²)=0
m(x+y)+n(x-y)-(m²+mn+n²)=0
=> (m + n)x + (m - n)y = m²+mn+n² Eq1
n(x+y)+m(x-y)-(m²-mn+n²)=0
=> (m + n)x - (m - n)y = m²-mn+n² Eq2
Adding both Eq1 + Eq2
=> 2(m+n)x = 2(m² + n²)
=> x = (m² + n²)/(m + n)
Eq1 - Eq2
=> 2y(m - n) = 2mn
=> y = mn/(m - n)
x = (m² + n²)/(m + n)
y = mn/(m - n)
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