Question

m1=50kg
r=20m
γ(gamma Γ)=6,67*10-11Nm2/kg2
Formula:F=(m1*m2)/r2

Answer 1

The question is that there are two masses m₁ and m₂  kept at a distance of r meters from each other.  Then to find the force of attraction between the two masses.

Newtons' law of gravitation says that Force
$F = G\frac{m_1 m_2}{ r^2},\ \ \ where\ G=6.67*10^{-11}\ N-m^2/kg^2$

We need to know the value of  m2 also to find the force.  Substitute the values in the given expression to find the answer.

 $F=6.67*10^{-11}*\frac{50*m_2}{20^2} Newtons\\\\.\ \ = 8.3375 * 10^{-12} * m_2\ Newtons$

The force depends on the value of mass of the second body.  If the mass m₂ = 50 kg also,  then the force = 4.16875 * 10⁻¹° Newtons.