Question

m²-4m=4 solve by quadratic formula​

Answer 1

Step-by-step explanation:

${\small{\sf{m^2 - 4m = 4}}}$

${\small{\sf{\implies{m^2 - 4m - 4 = 0}}}}$

We know that ,

Let,

a = 1

b = -4

c = -4

Now,

Put all the known values

${\small{\tt{ \dashrightarrow{\dfrac{-(-4) \pm \sqrt{(-4)^2 - 4(1)(-4)}}{2(1)}}}}}$

${\small{\tt{\dashrightarrow{\dfrac{4 \pm \sqrt{16 + 16}}{2}}}}}$

${\small{\tt{\dashrightarrow{\dfrac{4 \pm \sqrt{32}}{2}}}}}$

${\small{\tt{\dashrightarrow{\dfrac{4 \pm 4\sqrt{2}}{2}}}}}$

${\small{\tt{\dashrightarrow{\dfrac{{\cancel{4}}( 1 \pm \sqrt2)}{{\cancel{2}}}}}}}$

${\small{\tt{\longmapsto{ \pink{ \underline{ \boxed{\alpha = 2 + 2\sqrt2 \ \ and \ \ \beta = 2 - 2\sqrt2}}}}}}} \: \bigstar$