Question

m2so4*(m^+ monovalent metal ion ) solubility product =1.2×10^-5 at 298k .max concentration attained in saturated solution of this solid at 298k

Answer 1

Anwser:$1.44\times 10^{-2}$ will be the concentration.

Explanation:

              $M_2SO_4\rightarrow 2M^++SO_4^{2-}$

                       S                                   2S           S

When'S' mol/L of $M_2SO_4$ is dissolved in water, it gives 2S mol/ L of $M^+$ and 1S mol/ L of $SO_4^{2-}$.

Given = $K_{sp}=1.2\times 10^{-5}$

$K_{sp}=[2S]^2\times [S]$

$1.2\times 10^{-5}=4[S]^3$

$S=\sqrt[3] {\frac{1.2\times 10^{-5}}{4}}}=1.44\times 10^{-2}$ mol/L

The maximum concentration of $M_2SO_4$ at 298K will be $1.44\times 10^{-2}$ mol/L.

Answer 2

Applicable on all types of dibasic diacidic ksp questions accurate answers are obtained .