Ma 1. Limiting reactant is a reactant which limits the product formation. a) In the reaction between N2 and H2 to form NH3, which is the limiting reagent if 10g of N2 and 5g of H2 is used. (2) b)Find the amount of NH3 formed in the above condition. (2) . (
Answers
Answer:
Limiting reagent → The limiting reagent in a chemical reaction is the substance that is totally consumed when the chemical reaction is complete.
Given:-
Weight of N
2
=50kg=5×10
4
g
Weight of H
2
=10kg=10
4
g
Molecular weight of N
2
=28g
Molecular weight of H
2
=2g
As we know that,
No. of moles =
Mol. wt.
Weight
Therefore,
No. of moles of N
2
=
28
5×10
4
=1.786×10
3
moles
No. of moles of H
2
=
2
10
4
=5×10
3
moles
Now,
N
2
+3H
2
⟶2NH
3
From the above reaction,
1 mole of N
2
reacts with 3 moles of H
2
to produce 2 mole of ammonia.
Therefore,
1.786×10
3
moles of N
2
will react with 5.36×10
3
moles of H
2
to produce ammonia.
But given amount of H
2
is 5 moles.
Thus H
2
is limiting reagent.
Therefore,
Amount of ammonia produced by 3 moles of H
2
=2 moles
∴ Amount of ammonia produced by 5×10
3
moles of H
2
=
3
2
×5×10
3
=3.33×10
3
moles
Hence 3.33 moles of ammonia gas is formed.