Question

मी समद्विभुज
त्रिकोण आहे. माझा
पाया एकरूप
बाजूंच्या दुपटीपेक्षा 3
ने जास्त आहे. माझी
परिमिती 35 सेमी
आहे,तर माझ्या
पायाची लांबी किती?​

Answer 1

Given :- I am an isosceles triangle. My base is 3 more than double the same sides. My perimeter is 35 cm, so how long is my leg ?

Solution :-

Let us assume that, same sides of isosceles triangle are x cm each .

so,

→ Base of isosceles triangle = 3 more than the double same sides = 3 + 2 * x = (2x + 3) cm.

then,

→ Perimeter of isosceles triangle = 35cm.

→ x + x + (2x + 3) = 35

→ 4x = 35 - 3

→ 4x = 32

→ x = 8 cm.

therefore,

• Equal sides of isosceles triangle = 8 cm.
• Base = 2 * 8 + 3 = 16 + 3 = 19 cm.

But since we know that, in a triangle sum of any two sides is greater than the third sides.

But , we have,

• 8 + 8 < 19
• 16 < 19.

therefore, isosceles triangle with given data is not possible .

Learn more :-

*जर △ ABC ~ △ DEF असून AB = 12 सेमी and DE = 14 सेमी. तर △ ABC आणि △ DEF यांच्या क्षेत्रफळाचे गुणोत्तर किती?.*

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Answer 2

Given : An isosceles triangle.  

base is 3 cm more than  congruent sides.  

perimeter is 35 cm.

To Find :   the length of my base.

Solution:

congruent sides.    =   X  cm

Base = Y cm

base is 3 cm more than twice congruent sides.  

=> Y = X + 3

Perimeter  = X + X  + Y

=> 2X + y  = 35

=> 2X + X + 3 = 35

=> 3X  =  32

=> X  = 32/3  

Y = 32/3 + 3  =  41/3

Base = 41/3  cm

if use what given in question :

Then  base is 3 cm more than twice congruent sides.  

Y = 2X  + 3

=> 2X + 2X + 3 = 35

=> X = 8  and Y = 19

but such triangle is not possible as

19 > 8 + 8

and for a triangle sum of any two sides is greater than third side

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