Social Sciences, asked by XxDeadShotXx, 17 days ago

ma×va-mbvb=(ma+va)v

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Answered by llXxSnowflakexXll

4

G00GLE pr dekhle !! _____

Answered by Myxteria

1

Let us take masses of two objects mA and mB velocity=uA and uB Let them collide eachother object A exerts FAB on object B object B exerts FBA on object A Final velocity=vA and vB Momentum of object A is mA uA and mA v Rate of change of momentum =mA vA-uA/t similarly mB=uB-vB/t According to third law of motion FAB=FBA (OR) mAuA+mBuB=mAvA+mBvB

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