machine is purchased for rupees 2500 is value depreciated at the rate of 8% per annum will what will be its value after 2 years
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Answer:
Step-by-step explanation:
C.P of machine = 2500 Rs.
let the C.P. of machine be the principal(p),
Amount after 2 years = P (1 + r / 100)∧n
A = 2500 (1 - 8/100)∧2
A = 2500 (92 / 100)∧2
A = 2500 x 92/100 x 92/100
A = 2500 x 92 x 92 / 100 x 100
A = 2116 Rs
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