Question

machinery worth RS 10000 depreciated by5%.find its value after 1 year.rhe population of a city after 2years which is at present 12lakh if the rate of increase is 4percentage

Answer 1

1)

R = Initial Value = 10000

i = Rate of depreciation= 5%

n = time = 1 year

S = value after 1 year =

S = R(1 -i)^n

= 10000 ( 1 - 5/100)^1

= 10000( 1 - 0.05)

= 10000(0.95)

=9500 = value after 1 year



2)

S = Population after 2 years = ?

i = Annual growth rate = 4%

n = Duration = 2 years

R= population at the beginning = 12,00,000

S = R(1+i)^n

= 1200000( 1 + 4/100)^2

= 1200000( 1 + 0.04)^2

= 1200000(1.04)^2

= 1200000(1.0816)

=1200000(1.0816)

=1297920

1297920 = R = Population after 2 years