Magnetic field at the centre of circular loop of area a is
b.The magnetic moment of the loopis
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When a charged particle enters a magnetic field, it experience Lorentz force given by: dpdt=qv⃗ c×B⃗ dpdt=qv→c×B→
Since the force is cross product of particle’s velocity and magnetic field, it will be perpendicular to the direction of motion — the force does no work on the charge particle. Thus, the kinetic energy is unchanged—speed of the particle remains the same. The only thing it can change is the direction of the motion.
You can find the radius and time period of the circular motion by equating the above expression of mechanical force with the centripetal force give by: Fc=mv2r.
Since the force is cross product of particle’s velocity and magnetic field, it will be perpendicular to the direction of motion — the force does no work on the charge particle. Thus, the kinetic energy is unchanged—speed of the particle remains the same. The only thing it can change is the direction of the motion.
You can find the radius and time period of the circular motion by equating the above expression of mechanical force with the centripetal force give by: Fc=mv2r.
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