Question

Magnetic flux of 50 mw Wb is linked with a coil when a current of 0.1 mA passes through it. What is the self inductance of the coil

Answer 1

The self inductance of the coil is 0.5 H.

Explanation:

Given that,

Magnetic flux of the coil, $\phi=50\ \mu Wb=50\times 10^{-6}\ Wb$

Current in the coil, $I=0.1\ mA=0.1\times 10^{-3}\ A$

The self inductance of a coil is directly proportional to the current that is flowing through it as :

$\phi =L\times I$

L is the self inductance

$L=\dfrac{\phi}{I}$

$L=\dfrac{50\times 10^{-6}}{0.1\times 10^{-3}}$

L = 0.5 H

So, the self inductance of the coil is 0.5 H. Hence, this is the required solution.

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