15. Leena has 117 rupees in the form of 5 rupee coins and 2 rupee coins. The number of
2 rupee coins is 4 times that of 5 rupee coins. Find the number of coins of each
denomination.
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No of 5rs coins=x
No of 2rs coins=4x
Total money = 5x+4x×2=5x+8x=13x
13x=117
x=117/13=9
No of 5rs coins x=9
No of 2rs coins 4×9=36
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Answer:
9 coins of Rupee 5 and 36 coins of Rupee 2.
Step-by-step explanation:
Let the no. of coins of Rupee 5 coin be = x
No. of coins of Rupees 2 = 4x
Total money = ₹117
Now
Total money be rupee 5 coins = ₹5x
Total money by rupee 2 coins = ₹8x
No. of coins of each domination
= 5x + 8x = 117
= 13x = 117
= x = 117 ÷ 13
= x = 9
No. of coins of Rupee 5 = 9
No. of coins of Rupee 2 = ₹5x × 4 = 9 × 4 = 36
- Therefore, there are 9 coins of Rupee 5 and 36 coins of Rupee 2.
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