question - 3 2x-3y +6=0 2x+3y-18=0 solve by substitution method.
Answers
Question -
Solve the following pair of equations by substitution method -
2x-3y+6=0
2x+3y-18=0
Solution -
Given equations,
2x-3y+6=0......1)
And,
2x+3y-18=0
2x= 18-3y......2)
Substituting the value of 2x in equation 1) we will get -
Now,
Substituting the value of y in equation 2) we will get -
Verification -
=>2x-3y+6=0
Putting the values of x and y
=>2×3-3×4+6=0
=>6-12+6=0
=>12-12=0
=>0=0
Also,
=>2x+3y-18=0
Putting the values of x and y
=>2×3+3×4-18=0
=>6+12-18=0
=>18-18=0
=>0=0
L. H. S =R. H. S
Verified,
Therefore the value of x is 3 and y is 4
Question -
Solve the following pair of equations by substitution method -
2x-3y+6=0
2x+3y-18=0
Solution -
Given equations,
2x-3y+6=0......1)
And,
2x+3y-18=0
2x= 18-3y......2)
Substituting the value of 2x in equation 1) we will get -
\implies2x - 3y + 6 = 0⟹2x−3y+6=0
\implies18 - 3y - 3y + 6 = 0⟹18−3y−3y+6=0
\implies18 - 6y + 6 = 0⟹18−6y+6=0
\implies24 - 6y = 0⟹24−6y=0
\implies6y = 24⟹6y=24
\implies \: y = \frac{24}{6}⟹y=
6
24
\implies \: y = 4⟹y=4
Now,
Substituting the value of y in equation 2) we will get -
\implies2x = 18 - 3y⟹2x=18−3y
\implies2x = 18 - 3 \times 4⟹2x=18−3×4
\implies2x = 18 - 12⟹2x=18−12
\implies2x = 6⟹2x=6
\implies \: x = \frac{6}{2}⟹x=
2
6
\implies \: x = 3⟹x=3
Verification -
=>2x-3y+6=0
Putting the values of x and y
=>2×3-3×4+6=0
=>6-12+6=0
=>12-12=0
=>0=0
Also,
=>2x+3y-18=0
Putting the values of x and y
=>2×3+3×4-18=0
=>6+12-18=0
=>18-18=0
=>0=0
L. H. S =R. H. S
Verified,
Therefore the value of x is 3 and y is 4