Math, asked by good97104, 4 months ago

question - 3 2x-3y +6=0 2x+3y-18=0 solve by substitution method​.​

Answers

Answered by Bidikha
10

Question -

Solve the following pair of equations by substitution method -

2x-3y+6=0

2x+3y-18=0

Solution -

Given equations,

2x-3y+6=0......1)

And,

2x+3y-18=0

2x= 18-3y......2)

Substituting the value of 2x in equation 1) we will get -

\implies2x  - 3y + 6 = 0

\implies18 - 3y - 3y + 6 = 0

\implies18 - 6y + 6 = 0

\implies24 - 6y = 0

\implies6y = 24

\implies \: y =  \frac{24}{6}

\implies \: y = 4

Now,

Substituting the value of y in equation 2) we will get -

\implies2x = 18 - 3y

\implies2x = 18 - 3 \times 4

\implies2x = 18 - 12

\implies2x = 6

\implies \: x =  \frac{6}{2}

\implies \: x = 3

Verification -

=>2x-3y+6=0

Putting the values of x and y

=>2×3-3×4+6=0

=>6-12+6=0

=>12-12=0

=>0=0

Also,

=>2x+3y-18=0

Putting the values of x and y

=>2×3+3×4-18=0

=>6+12-18=0

=>18-18=0

=>0=0

L. H. S =R. H. S

Verified,

Therefore the value of x is 3 and y is 4

Answered by mahek77777
9

Question -

Solve the following pair of equations by substitution method -

2x-3y+6=0

2x+3y-18=0

Solution -

Given equations,

2x-3y+6=0......1)

And,

2x+3y-18=0

2x= 18-3y......2)

Substituting the value of 2x in equation 1) we will get -

\implies2x - 3y + 6 = 0⟹2x−3y+6=0

\implies18 - 3y - 3y + 6 = 0⟹18−3y−3y+6=0

\implies18 - 6y + 6 = 0⟹18−6y+6=0

\implies24 - 6y = 0⟹24−6y=0

\implies6y = 24⟹6y=24

\implies \: y = \frac{24}{6}⟹y=

6

24

\implies \: y = 4⟹y=4

Now,

Substituting the value of y in equation 2) we will get -

\implies2x = 18 - 3y⟹2x=18−3y

\implies2x = 18 - 3 \times 4⟹2x=18−3×4

\implies2x = 18 - 12⟹2x=18−12

\implies2x = 6⟹2x=6

\implies \: x = \frac{6}{2}⟹x=

2

6

\implies \: x = 3⟹x=3

Verification -

=>2x-3y+6=0

Putting the values of x and y

=>2×3-3×4+6=0

=>6-12+6=0

=>12-12=0

=>0=0

Also,

=>2x+3y-18=0

Putting the values of x and y

=>2×3+3×4-18=0

=>6+12-18=0

=>18-18=0

=>0=0

L. H. S =R. H. S

Verified,

Therefore the value of x is 3 and y is 4

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