Question

Magnetic moment of Fea+(z=26) is √24BM.Hence number of unpaired electrons and value of a respectively are :

Answer 1

MAGNETIC MOMENT=√N(N+2)

√24=√N(N+2)

24=N^2+2N

N^2+2N-24=0

AFTER SOLVING THIS WE GET

N=4

SO IN THE COMPOUND FE+ THERE WILL BE 4 UNPAIRED ELECTRONS

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