magnitude of an angle which is 2/3 of its supplement
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let the angle be x°
so x = 2/3(180°-x)
=> x = 120 - 2/3x
=> x + 2/3x = 120°
=> 5/3x = 120°
=> x = 72°
hope it helps u plzz mark as brainliest I need it plzz
so x = 2/3(180°-x)
=> x = 120 - 2/3x
=> x + 2/3x = 120°
=> 5/3x = 120°
=> x = 72°
hope it helps u plzz mark as brainliest I need it plzz
simransahu94:
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