Question

Magnitude of equilibrant of two forces F1 and F2 acting normally to each other is 50 KN. If magnitude of force F1 is 40 KN, then magnitude of force F2 will be

1) 30 KN 2) 1.33 KN 3) 12.00KN 4) 26.45 KN​

Answer 1

Answer:

30 KN

Explanation:

Since two forces are perpendicular to each other so we can use vector sum

Total Force = ( F1^2 + F2^2)^1/2

50 = √ (40)^2 + (x)^2

2500 = 1600 + x^2

x^2 = 2500-1600

x^2 = 900

x = √900 = 30 KN

Answer 2

The magnitude of force $F_2$ is 30 KN.

Explanation:

It is given that,

Magnitude of force 1, $F_1=40\ KN$

Magnitude of two forces that are perpendicular to each other, F = 50 KN

We need to find the magnitude of force $F_2$. The magnitude of two vectors that are perpendicular to each other is given by :

$F=\sqrt{F_1^2+F_2^2}$

$50=\sqrt{(40)^2+F_2^2}$

On solving, $F_2=30\ KN$

So, the magnitude of force $F_2$ is 30 KN. Hence, the correct option is (1).

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Vectors

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