Question

magnitude of resultant r vector
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Answer 1

Answer:here is your answrr in pic

Answer 2

Answer:

$\large \vec R=\sqrt{P^2+Q^2+2PQ \ \cos\theta}$

Explanation:

The magnitude of resultant R vector as

$\large \vec R=\sqrt{P^2+Q^2+2PQ \ \cos\theta}$

Taking one example for it.

Suppose we have two vectors P and Q having magnitude 3 & 4 unit and angle between them is 90.

We have to find magnitude of resultant .

We know value of cos 90 = 0

Put the values in formula we get

$\large \vec R=\sqrt{3^2+4^2+2\times3\times4\times0}\\\\\\\large \vec R=\sqrt{9+16+0}\\\\\\\large \vec R=\sqrt{25}\\\\\\\large \vec R=5 \ unit$

Thus we get answer 5 unit as magnitude of resultant.