Question

Magnitude of the food
An object of masss 5 kg is moving with a velocity of
loms! A force is applied that in 20s, it attains a
velocity of 25ms". what is the force applied on the
object?​

Answer 1

Correct Question :

• An object of masss 5 kg is moving with a velocity of 10 m/s a force is applied that in 20s, it attains a velocity of 25m/s . what is the force applied on the object?

Explanation :

Given :

• Mass of an object (m) = 5 kg
• Initial velocity (u) = 10 m/s
• Final velocity (v) = 25 m/s
• Time (t) = 20 s

To Find :

• The force applied on the object?

Solution :

Apply 1st equation of motion,

$\tt \green{a = \dfrac{v - u}{t} }$

Now,

$\tt \longrightarrow \: a = \dfrac{25 - 10}{20} \\ \\ \tt \longrightarrow \: a = \dfrac{15}{10} \\ \\ \tt \longrightarrow \red{ a =1.5 \: ms {}^{ - 2} }$

According to the 2nd law of motion,

$\tt \pink{F = m \times a}$

Now,

$\tt \longrightarrow \: F =5 \times 1.5 \\ \\ \tt \longrightarrow \purple{ F =7.5 \: N}$

Hence :

The force applied on the object is 7.5 N.

Answer 2

$\large \mathfrak{ \underline{ \color{navy}{Correct Question :}}}$

An object of masss 5 kg is moving with a velocity of 10 m/s a force is applied that in 20s, it attains a velocity of 25m/s . What is the force applied on the object?

$\large \mathfrak{ \underline{ \color{green}{Given: }}}$

• Mass of an object (m) = 5 kg

• Initial velocity (u) = 10 m/s

• Final velocity (v) = 25 m/s

• Time (t) = 20 s

$\large \mathfrak{ \underline{ \color{purple}{To Find :}}}$

• The force applied on the object.

$\large \mathfrak{ \underline{ \color{chocolate}{Solution : }}}$

$\sf{ \color{teal}{Apply 1st equation of motion,}}$

$\ \pink{a = \dfrac{v - u}{t} }$

Now,

$\begin{gathered}\sf \implies \: { \red{a = \dfrac{25 - 10}{20}}} \\ \\ \sf\implies \: { \red{a = \dfrac{15}{10}}} \\ \\ \boxed{ \sf\implies \red{ a =1.5 \: ms {}^{ - 2} }}\end{gathered}$

$\sf{ \color{teal}{According to the 2nd law of motion,}}$

$\pink{F = m \times a}$

Now,

$\begin{gathered}\sf \implies\:{ \red{ F =5 \times 1.5 }}\\ \\ \boxed{\sf \implies\red{ F =7.5 \: N}}\end{gathered}</p><p>$

$\sf{ \purple{\therefore \: The \: force \: applied \: on \: the \: object \: is \: 7.5 N.}}$