Question

Mahendra and Virat are sitting at a distance of 1 m from each other their masses are assigned 75 kg and 80 kg respectively what is the gravitational force between them

Answer 1

use the formula GMm/r^2
G=6.67×10^-11

Answer 2

Explanation :

Given that,

Mahendra's mass, $m_1=75 kg$

Virat's mass, $m_2=80 kg$

Distance between Mahendra and Virat is , d = 1 m

Gravitational force is given by :

$F=G\dfrac{m_1m_2}{d^2}$

G is universal gravitational constant

$G=6.67\times 10^{-11}\ m^3kg^{-1}s^{-2}$

So,

$F=6.67\times 10^{-11}\ m^3kg^{-1}s^{-2}\times \dfrac{75\ kg\times 80\ kg}{(1\ m)^2}$

$F=4.002\times 10^{-7}\ N$

Hence, this is the required solution.