Question

Mahendra and Virat are sitting

at a distance of 1 metre from each other. Their
masses are 75 kg and 80 kg respectively.

What is the gravitational force between them?​

Answer 1

Explanation:

Given :-

Radius = 1 m

m₁ = 75 kg

m₂ = 80 kg

G = 6.67 × 10⁻¹¹ Nm²/kg²

To Find :-

Gravitational force between them.

Formula to be used :-

Newton's Law i.e F = Gm₁m₂/r²

Solution :-

Putting all the values,we get

F = Gm₁m₂/r²

F = 6.67 × 10⁻¹¹ × 75 × 80/1² n

F = 4.002 × 10⁻⁷ N

Hence, the gravitational force between Mahesh and virat 4.002 × 10⁻⁷ N.

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