Question

Mahendra and Virat are sitting

at a distance of 1 metre from each other. Their

masses are 75 kg and 80 kg respectively.

What is the gravitational force between them?​

Answer 1

Answer:

Given : r = 1 m, m1

= 75 kg, m2

= 80 kg and

G = 6.67 x 10 -11 Nm2/kg2

According to Newton’s law

F = G m1m2/ r2

F = 6.67 x 10-11 x 75 x 80 / {1}^{2}

= 4.002 x 10-7 N

The gravitational force between Mahendra

and Virat is 4.002 x 10-7 N

This is a very small force. If the force of

friction between Mahendra and the bench on

which he is sitting is zero, then he will start

moving towards Virat under the action of

this force. We can calculate his acceleration

and velocity by using Newton’s laws of motion.

I hope this will be helpful for you

Have a nice day ❤️❤️❤️