What number should be added to each of the number 12, 22,42 and 72 so that that resulting number may be in proportion
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Answer:
3 should be added to each of the number 12, 22,42 and 72 so that that resulting number may be in proportion.
Step-by-step explanation:
Let
x should be added.
First number= 12 +x.
Second number =22 + x.
Third number = 42 + x.
Forth number = 72 + x.
( 12 + x ) : ( 22 + x ) :: ( 42 + x ) : ( 72 + x )
Product of extremes = Product of means.
( 12 + x ) (72 + x ) = ( 42 + x ) ( 22 + x )
(12×72) + 12x + 72x + x ^2 = (42×22) + 42x + 22x + x ^2
864 + 84x + x ^2 =924 + 64x + x ^2
84x - 64x + x ^2- x ^2 = 924−864
20 x = 60
x = 60 / 20
x = 3.
3 should be added to each of the number 12, 22,42 and 72 so that that resulting number may be in proportion.
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