Math, asked by mandalsubham394, 1 month ago

mahesh borrowed a certain sum for two years at simple interest from bhim. mahesh lent this sum to vishnu at the same rate for two years compound interest. at the end of two years, mahesh received 400 as simple interest. find the sum and rate of interest.​

Answers

Answered by rs8696565
0

Answer:

mahesh borrowed a certain sum for two years at simple interest from bhim. mahesh lent this sum to vishnu at the same rate for two years compound interest. at the end of two years, mahesh received 400 as simple interest. find the sum and rate of interest.

Step-by-step explanation:

mahesh borrowed a certain sum for two years at simple interest from bhim. mahesh lent this sum to vishnu at the same rate for two years compound interest. at the end of two years, mahesh received 400 as simple interest. find the sum and rate of interest.

( this question ). may be its help for you

Answered by studay07
1

Answer:

Let the principal be P, interest rate be r and time period be n, then for the compound interest the formula will be

A=P(1+r/100)^n - P

and simple interest will be A=Pnr/100.

Mahesh borrowed a certain sum for two years at simple interest from Bhim. Mahesh lent his sum to Vishnu at the same rate for two years compound interest.

Let us assume the amount is P and the rate is r.

So, according to the formula Mahesh will pay for the simple interest

A1=P×2×r/100=400

and he will get for the compound interest

A2=P(1+r/100)2^−P=410

Simplifying A2=P(1+r/100)^2−P=410, we get

P(1+r/100+1 (1+r/100−1)=410

⇒Pr/100[(2+r/100)]=410

From A1=P×2×r/100=400, we get

Pr=20000 .

Putting the value in Pr/100(2+r/100)=410, we get

20000/100(2+r/100)=410

⇒2+r/100=410/200

⇒r/100=410/200−2

=10/200

⇒r=5

Now putting the value of r=5 in the equation of Pr=20000, we get

P×5=20000

⇒P=20000/5=4000

Therefore the sum is 4000

Therefore the sum is 4000And the Interest is 5%

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