Mahesh borrowed a certain sum of money for two years at simple interest from bhin. Mahesh lent this sum to vishnu at the same rate for two yrs compound interest. At the end of two yrs, mahesh received rs 410 as compound interest but paid rs 400 as simple ineteres. Find the sum ane rate of interest.
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SI for 2yr = 400
SI for each year= 400/2=200
SI and CI are always same at the end of 1st yr
CI of 1st yr= 200
CI for 2nd yr= 410-200=210
CI of rs200 is rs10
CI of rs 1 is 10/200
Therefore CI of rs 100= 10*100/200 =5%
SI = 400
T = 2yr
R= 5%
P= SI*100/r*t
400*100/5*2
= 4000
Hope this will help uu....
SI for each year= 400/2=200
SI and CI are always same at the end of 1st yr
CI of 1st yr= 200
CI for 2nd yr= 410-200=210
CI of rs200 is rs10
CI of rs 1 is 10/200
Therefore CI of rs 100= 10*100/200 =5%
SI = 400
T = 2yr
R= 5%
P= SI*100/r*t
400*100/5*2
= 4000
Hope this will help uu....
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